Variable Substitution in Shell

$

Let us carefully distinguish between the name of a variable and its value. If variable1 is the name of a variable, then $variable1 is a reference to its value, the data item it contains. [1]

bash$ variable=23

bash$ echo variable

variable

bash$ echo $variable

23

The only time a variable appears "naked" -- without the $ prefix -- is when declared or assigned, when unset, when exported, or in the special case of a variable representing a signal (see Example 29-5). Assignment may be with an = (as in var1=27), in a read statement, and at the head of a loop (for var2 in 1 2 3).

Enclosing a referenced value in double quotes (" ... ") does not interfere with variable substitution. This is called partial quoting, sometimes referred to as "weak quoting." Using single quotes (' ... ') causes the variable name to be used literally, and no substitution will take place. This is full quoting, sometimes referred to as 'strong quoting.'

Note that $variable is actually a simplified form of ${variable}. In contexts where the $variable syntax causes an error, the longer form may work (see Section 9.3, below).

Example 4-1. Variable assignment and substitution

#!/bin/bash

# ex9.sh

# Variables: assignment and substitution

a=375

hello=$a

#-------------------------------------------------------------------------

# No space permitted on either side of = sign when initializing variables.

# What happens if there is a space?

# "VARIABLE =value"

# ^

#% Script tries to run "VARIABLE" command with one argument, "=value".

# "VARIABLE= value"

# ^

#% Script tries to run "value" command with

#+ the environmental variable "VARIABLE" set to "".

#-------------------------------------------------------------------------

echo hello # hello

# Not a variable reference, just the string "hello" . . .

echo $hello # 375

# ^ This *is* a variable reference.

echo ${hello} # 375

# Also a variable reference, as above.

# Quoting . . .

echo "$hello" # 375

echo "${hello}" # 375

echo

hello="A B C D"

echo $hello # A B C D

echo "$hello" # A B C D

# As you see, echo $hello and echo "$hello" give different results.

# Why?

# =======================================

# Quoting a variable preserves whitespace.

# =======================================

echo

echo '$hello' # $hello

# ^ ^

# Variable referencing disabled (escaped) by single quotes,

#+ which causes the "$" to be interpreted literally.

# Notice the effect of different types of quoting.

hello= # Setting it to a null value.

echo "$hello (null value) = $hello"

# Note that setting a variable to a null value is not the same as

#+ unsetting it, although the end result is the same (see below).

# --------------------------------------------------------------

# It is permissible to set multiple variables on the same line,

#+ if separated by white space.

# Caution, this may reduce legibility, and may not be portable.

var1=21 var2=22 var3=$V3

echo

echo "var1=$var1 var2=$var2 var3=$var3"

# May cause problems with older versions of "sh" . . .

# --------------------------------------------------------------

echo; echo

numbers="one two three"

# ^ ^

other_numbers="1 2 3"

# ^ ^

# If there is whitespace embedded within a variable,

#+ then quotes are necessary.

# other_numbers=1 2 3 # Gives an error message.

echo "numbers = $numbers"

echo "other_numbers = $other_numbers" # other_numbers = 1 2 3

# Escaping the whitespace also works.

mixed_bag=2 --- Whatever

# ^ ^ Space after escape ().

echo "$mixed_bag" # 2 --- Whatever

echo; echo

echo "uninitialized_variable = $uninitialized_variable"

# Uninitialized variable has null value (no value at all!).

uninitialized_variable= # Declaring, but not initializing it --

#+ same as setting it to a null value, as above.

echo "uninitialized_variable = $uninitialized_variable"

# It still has a null value.

uninitialized_variable=23 # Set it.

unset uninitialized_variable # Unset it.

echo "uninitialized_variable = $uninitialized_variable"

# It still has a null value.

echo

exit 0

Caution

An uninitialized variable has a "null" value -- no assigned value at all (not zero!).

if [ -z "$unassigned" ]

then

echo "$unassigned is NULL."

fi # $unassigned is NULL.

Using a variable before assigning a value to it may cause problems. It is nevertheless possible to perform arithmetic operations on an uninitialized variable.

echo "$uninitialized" # (blank line)

let "uninitialized += 5" # Add 5 to it.

echo "$uninitialized" # 5

# Conclusion:

# An uninitialized variable has no value,

#+ however it acts as if it were 0 in an arithmetic operation.

# This is undocumented (and probably non-portable) behavior,

#+ and should not be used in a script.

Notes

[1]

Technically, the name of a variable is called an lvalue, meaning that it appears on the left side of an assignment statment, as in VARIABLE=23. A variable's value is an rvalue, meaning that it appears on the right side of an assignment statement, as in VAR2=$VARIABLE.

A variable's name is, in fact, a reference, a pointer to the memory location(s) where the actual data associated with that variable is kept.

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